(n^2-9)(n+4)=0

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Solution for (n^2-9)(n+4)=0 equation: 


Simplifying
(n2 + -9)(n + 4) = 0

Reorder the terms:
(-9 + n2)(n + 4) = 0

Reorder the terms:
(-9 + n2)(4 + n) = 0

Multiply (-9 + n2) * (4 + n)
(-9(4 + n) + n2(4 + n)) = 0
((4 * -9 + n * -9) + n2(4 + n)) = 0
((-36 + -9n) + n2(4 + n)) = 0
(-36 + -9n + (4 * n2 + n * n2)) = 0
(-36 + -9n + (4n2 + n3)) = 0
(-36 + -9n + 4n2 + n3) = 0

Solving
-36 + -9n + 4n2 + n3 = 0

Solving for variable 'n'.

The solution to this equation could not be determined.

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